Concept of Cloud Computers: (12 minutes)
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Introduction to Parallel Computing: (3 minutes)
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Introduction to Parallel Computing: (3 minutes)
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Sunday 16 December 2018
Friday 14 December 2018
Thursday 13 December 2018
Wednesday 5 December 2018
Thursday 29 November 2018
11-C String comparison in python
You can use ( > , < , <= , <= , == , != ) to compare two strings. Python compares string lexicographically i.e using ASCII value of the characters.
Suppose you have str1 as "Mary" and str2 as "Mac" . The first two characters from str1 and str2 ( M and M ) are compared. As they are equal, the second two characters are compared. Because they are also equal, the third two characters ( r and c) are compared. And because 'r' has greater ASCII value than 'c' , str1 is greater than str2 .
Here are some more examples:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
|
>>> "tim" == "tie"
False
>>> "free" != "freedom"
True
>>> "arrow" > "aron"
True
>>> "right" >= "left"
True
>>> "teeth" < "tee"
False
>>> "yellow" <= "fellow"
False
>>> "abc" > ""
True
>>>
|
Wednesday 21 November 2018
11-C Prog- Write a algorithm and program sorting the elements using Bubble sort through function
Graphics; Click Here
def b_s(n):
l=[]
for i in range(n):
num=int(input("enter the number:"))
l.append(num)
#bubble sort
for k in range(0,n,1):
for j in range(0,n-1,1):
if l[j]>l[j+1]:
t=l[j]
l[j]=l[j+1]
l[j+1]=t
print("Stage=",k+1,"inside list=",j+1,"=",l)
print("Stage=",k+1,"Final list=",l)
print("Final Result list=:",l)
#main program
n=int(input("enter size of list:"))
print("size of list:",n)
b_s(n)
Input
enter size of list:5
size of list: 5
enter the number:5
enter the number:2
enter the number:7
enter the number:10
enter the number:1
Output
Stage= 1 inside list= 1 = [2, 5, 7, 10, 1]
Stage= 1 inside list= 2 = [2, 5, 7, 10, 1]
Stage= 1 inside list= 3 = [2, 5, 7, 10, 1]
Stage= 1 inside list= 4 = [2, 5, 7, 1, 10]
Stage= 1 Final list= [2, 5, 7, 1, 10]
Stage= 2 inside list= 1 = [2, 5, 7, 1, 10]
Stage= 2 inside list= 2 = [2, 5, 7, 1, 10]
Stage= 2 inside list= 3 = [2, 5, 1, 7, 10]
Stage= 2 inside list= 4 = [2, 5, 1, 7, 10]
Stage= 2 Final list= [2, 5, 1, 7, 10]
Stage= 3 inside list= 1 = [2, 5, 1, 7, 10]
Stage= 3 inside list= 2 = [2, 1, 5, 7, 10]
Stage= 3 inside list= 3 = [2, 1, 5, 7, 10]
Stage= 3 inside list= 4 = [2, 1, 5, 7, 10]
Stage= 3 Final list= [2, 1, 5, 7, 10]
Stage= 4 inside list= 1 = [1, 2, 5, 7, 10]
Stage= 4 inside list= 2 = [1, 2, 5, 7, 10]
Stage= 4 inside list= 3 = [1, 2, 5, 7, 10]
Stage= 4 inside list= 4 = [1, 2, 5, 7, 10]
Stage= 4 Final list= [1, 2, 5, 7, 10]
Stage= 5 inside list= 1 = [1, 2, 5, 7, 10]
Stage= 5 inside list= 2 = [1, 2, 5, 7, 10]
Stage= 5 inside list= 3 = [1, 2, 5, 7, 10]
Stage= 5 inside list= 4 = [1, 2, 5, 7, 10]
Stage= 5 Final list= [1, 2, 5, 7, 10]
Final Result list=: [1, 2, 5, 7, 10]
Input
enter size of list:5
size of list: 5
enter the number: 6
enter the number: 5
enter the number: 4
enter the number: 3
enter the number: 1
Output
Stage= 1 inside list= 1 = [5, 6, 4, 3, 1]
Stage= 1 inside list= 2 = [5, 4, 6, 3, 1]
Stage= 1 inside list= 3 = [5, 4, 3, 6, 1]
Stage= 1 inside list= 4 = [5, 4, 3, 1, 6]
Stage= 1 Final list= [5, 4, 3, 1, 6]
Stage= 2 inside list= 1 = [4, 5, 3, 1, 6]
Stage= 2 inside list= 2 = [4, 3, 5, 1, 6]
Stage= 2 inside list= 3 = [4, 3, 1, 5, 6]
Stage= 2 inside list= 4 = [4, 3, 1, 5, 6]
Stage= 2 Final list= [4, 3, 1, 5, 6]
Stage= 3 inside list= 1 = [3, 4, 1, 5, 6]
Stage= 3 inside list= 2 = [3, 1, 4, 5, 6]
Stage= 3 inside list= 3 = [3, 1, 4, 5, 6]
Stage= 3 inside list= 4 = [3, 1, 4, 5, 6]
Stage= 3 Final list= [3, 1, 4, 5, 6]
Stage= 4 inside list= 1 = [1, 3, 4, 5, 6]
Stage= 4 inside list= 2 = [1, 3, 4, 5, 6]
Stage= 4 inside list= 3 = [1, 3, 4, 5, 6]
Stage= 4 inside list= 4 = [1, 3, 4, 5, 6]
Stage= 4 Final list= [1, 3, 4, 5, 6]
Stage= 5 inside list= 1 = [1, 3, 4, 5, 6]
Stage= 5 inside list= 2 = [1, 3, 4, 5, 6]
Stage= 5 inside list= 3 = [1, 3, 4, 5, 6]
Stage= 5 inside list= 4 = [1, 3, 4, 5, 6]
Stage= 5 Final list= [1, 3, 4, 5, 6]
Final Result list=: [1, 3, 4, 5, 6]
>>>
def b_s(n):
l=[]
for i in range(n):
num=int(input("enter the number:"))
l.append(num)
#bubble sort
for k in range(0,n,1):
for j in range(0,n-1,1):
if l[j]>l[j+1]:
t=l[j]
l[j]=l[j+1]
l[j+1]=t
print("Stage=",k+1,"inside list=",j+1,"=",l)
print("Stage=",k+1,"Final list=",l)
print("Final Result list=:",l)
#main program
n=int(input("enter size of list:"))
print("size of list:",n)
b_s(n)
Input
enter size of list:5
size of list: 5
enter the number:5
enter the number:2
enter the number:7
enter the number:10
enter the number:1
Output
Stage= 1 inside list= 1 = [2, 5, 7, 10, 1]
Stage= 1 inside list= 2 = [2, 5, 7, 10, 1]
Stage= 1 inside list= 3 = [2, 5, 7, 10, 1]
Stage= 1 inside list= 4 = [2, 5, 7, 1, 10]
Stage= 1 Final list= [2, 5, 7, 1, 10]
Stage= 2 inside list= 1 = [2, 5, 7, 1, 10]
Stage= 2 inside list= 2 = [2, 5, 7, 1, 10]
Stage= 2 inside list= 3 = [2, 5, 1, 7, 10]
Stage= 2 inside list= 4 = [2, 5, 1, 7, 10]
Stage= 2 Final list= [2, 5, 1, 7, 10]
Stage= 3 inside list= 1 = [2, 5, 1, 7, 10]
Stage= 3 inside list= 2 = [2, 1, 5, 7, 10]
Stage= 3 inside list= 3 = [2, 1, 5, 7, 10]
Stage= 3 inside list= 4 = [2, 1, 5, 7, 10]
Stage= 3 Final list= [2, 1, 5, 7, 10]
Stage= 4 inside list= 1 = [1, 2, 5, 7, 10]
Stage= 4 inside list= 2 = [1, 2, 5, 7, 10]
Stage= 4 inside list= 3 = [1, 2, 5, 7, 10]
Stage= 4 inside list= 4 = [1, 2, 5, 7, 10]
Stage= 4 Final list= [1, 2, 5, 7, 10]
Stage= 5 inside list= 1 = [1, 2, 5, 7, 10]
Stage= 5 inside list= 2 = [1, 2, 5, 7, 10]
Stage= 5 inside list= 3 = [1, 2, 5, 7, 10]
Stage= 5 inside list= 4 = [1, 2, 5, 7, 10]
Stage= 5 Final list= [1, 2, 5, 7, 10]
Final Result list=: [1, 2, 5, 7, 10]
Input
enter size of list:5
size of list: 5
enter the number: 6
enter the number: 5
enter the number: 4
enter the number: 3
enter the number: 1
Output
Stage= 1 inside list= 1 = [5, 6, 4, 3, 1]
Stage= 1 inside list= 2 = [5, 4, 6, 3, 1]
Stage= 1 inside list= 3 = [5, 4, 3, 6, 1]
Stage= 1 inside list= 4 = [5, 4, 3, 1, 6]
Stage= 1 Final list= [5, 4, 3, 1, 6]
Stage= 2 inside list= 1 = [4, 5, 3, 1, 6]
Stage= 2 inside list= 2 = [4, 3, 5, 1, 6]
Stage= 2 inside list= 3 = [4, 3, 1, 5, 6]
Stage= 2 inside list= 4 = [4, 3, 1, 5, 6]
Stage= 2 Final list= [4, 3, 1, 5, 6]
Stage= 3 inside list= 1 = [3, 4, 1, 5, 6]
Stage= 3 inside list= 2 = [3, 1, 4, 5, 6]
Stage= 3 inside list= 3 = [3, 1, 4, 5, 6]
Stage= 3 inside list= 4 = [3, 1, 4, 5, 6]
Stage= 3 Final list= [3, 1, 4, 5, 6]
Stage= 4 inside list= 1 = [1, 3, 4, 5, 6]
Stage= 4 inside list= 2 = [1, 3, 4, 5, 6]
Stage= 4 inside list= 3 = [1, 3, 4, 5, 6]
Stage= 4 inside list= 4 = [1, 3, 4, 5, 6]
Stage= 4 Final list= [1, 3, 4, 5, 6]
Stage= 5 inside list= 1 = [1, 3, 4, 5, 6]
Stage= 5 inside list= 2 = [1, 3, 4, 5, 6]
Stage= 5 inside list= 3 = [1, 3, 4, 5, 6]
Stage= 5 inside list= 4 = [1, 3, 4, 5, 6]
Stage= 5 Final list= [1, 3, 4, 5, 6]
Final Result list=: [1, 3, 4, 5, 6]
>>>
11-C Prog- Counting the number of operation while sorting the elements
#INSERTION SORTING
def ins_sort(n):
alist=[]
for i in range(n):
num=int(input("Enter the number"))
alist.append(num)
count=0
print("Original list is:",alist)
for i in range (1,len(alist)):
key=alist[i]
j=i-1
while j>=0 and key < alist[j]:
alist[j+1]=alist[j]
j=j-1
else:
alist[j+1]=key
count=count+1
print("steps=",i,"list=",alist)
print("list after sorting using insertion sort:",alist)
print("The number of operation while sorting the elements in insertion sort method is=",count)
#main program
n=int(input("Enter the size of insertion sort"))
ins_sort(n)
>>>
= RESTART: C:/Users/Student/AppData/Local/Programs/Python/Python37-32/ins.py =
Input
Enter the size of insertion sort 5
Enter the number 6
Enter the number 5
Enter the number 4
Enter the number 3
Enter the number 1
Original list is: [6, 5, 4, 3, 1]
Output
steps= 1 list= [5, 6, 4, 3, 1]
steps= 2 list= [4, 5, 6, 3, 1]
steps= 3 list= [3, 4, 5, 6, 1]
steps= 4 list= [1, 3, 4, 5, 6]
list after sorting using insertion sort: [1, 3, 4, 5, 6]
The number of operation while sorting the elements in insertion sort method is = 4
#BUBBLE SORTING
def b_s(n):
l=[]
for i in range(n):
num=int(input("enter the number:"))
l.append(num)
count=0
#bubble sort
for k in range(0,n,1):
for j in range(0,n-1,1):
if l[j]>l[j+1]:
t=l[j]
l[j]=l[j+1]
l[j+1]=t
count=count+1
print("Stage=",k+1,"inside list=",j+1,"=",l)
print("Stage=",k+1,"Final list=",l)
print("Final Result list=:",l)
print("The number of operation while sorting the elements in bubble sort method is=",count)
#main program
n=int(input("enter size of list:"))
print("size of list:",n)
b_s(n)
Input
enter size of list:5
size of list: 5
enter the number: 6
enter the number: 5
enter the number: 4
enter the number: 3
enter the number: 1
Output
Stage= 1 inside list= 1 = [5, 6, 4, 3, 1]
Stage= 1 inside list= 2 = [5, 4, 6, 3, 1]
Stage= 1 inside list= 3 = [5, 4, 3, 6, 1]
Stage= 1 inside list= 4 = [5, 4, 3, 1, 6]
Stage= 1 Final list= [5, 4, 3, 1, 6]
Stage= 2 inside list= 1 = [4, 5, 3, 1, 6]
Stage= 2 inside list= 2 = [4, 3, 5, 1, 6]
Stage= 2 inside list= 3 = [4, 3, 1, 5, 6]
Stage= 2 inside list= 4 = [4, 3, 1, 5, 6]
Stage= 2 Final list= [4, 3, 1, 5, 6]
Stage= 3 inside list= 1 = [3, 4, 1, 5, 6]
Stage= 3 inside list= 2 = [3, 1, 4, 5, 6]
Stage= 3 inside list= 3 = [3, 1, 4, 5, 6]
Stage= 3 inside list= 4 = [3, 1, 4, 5, 6]
Stage= 3 Final list= [3, 1, 4, 5, 6]
Stage= 4 inside list= 1 = [1, 3, 4, 5, 6]
Stage= 4 inside list= 2 = [1, 3, 4, 5, 6]
Stage= 4 inside list= 3 = [1, 3, 4, 5, 6]
Stage= 4 inside list= 4 = [1, 3, 4, 5, 6]
Stage= 4 Final list= [1, 3, 4, 5, 6]
Stage= 5 inside list= 1 = [1, 3, 4, 5, 6]
Stage= 5 inside list= 2 = [1, 3, 4, 5, 6]
Stage= 5 inside list= 3 = [1, 3, 4, 5, 6]
Stage= 5 inside list= 4 = [1, 3, 4, 5, 6]
Stage= 5 Final list= [1, 3, 4, 5, 6]
Final Result list=: [1, 3, 4, 5, 6]
The number of operation while sorting the elements in bubble sort method is = 20
Tuesday 13 November 2018
11-C 29 Write a algorithm and python program sorting the numbers using insertion through function
Graphics Click Here
def ins_sort(n):
alist=[]
for i in range(n):
num=int(input("Enter the number"))
alist.append(num)
print("Original list is:",alist)
for i in range (1,len(alist)):
key=alist[i]
j=i-1
while j>=0 and key < alist[j]:
alist[j+1]=alist[j]
j=j-1
else:
alist[j+1]=key
print("step=",i,"list=",alist)
print("list after sorting using insertion sort:",alist)
#main program
n=int(input("Enter the size of insertion sort"))
ins_sort(n)
def ins_sort(n):
alist=[]
for i in range(n):
num=int(input("Enter the number"))
alist.append(num)
print("Original list is:",alist)
for i in range (1,len(alist)):
key=alist[i]
j=i-1
while j>=0 and key < alist[j]:
alist[j+1]=alist[j]
j=j-1
else:
alist[j+1]=key
print("step=",i,"list=",alist)
print("list after sorting using insertion sort:",alist)
#main program
n=int(input("Enter the size of insertion sort"))
ins_sort(n)
>>>
= RESTART: C:/Users/Student/AppData/Local/Programs/Python/Python37-32/ins.py =
Input
Enter the size of insertion sort 5
Enter the number 6
Enter the number 5
Enter the number 4
Enter the number 3
Enter the number 1
Original list is: [6, 5, 4, 3, 1]
Output
steps= 1 list= [5, 6, 4, 3, 1]
steps= 2 list= [4, 5, 6, 3, 1]
steps= 3 list= [3, 4, 5, 6, 1]
steps= 4 list= [1, 3, 4, 5, 6]
list after sorting using insertion sort: [1, 3, 4, 5, 6]
>>>
Input
Enter the size of insertion sort 5
Enter the number 6
Enter the number 5
Enter the number 4
Enter the number 3
Enter the number 1
Original list is: [6, 5, 4, 3, 1]
Output
steps= 1 list= [5, 6, 4, 3, 1]
steps= 2 list= [4, 5, 6, 3, 1]
steps= 3 list= [3, 4, 5, 6, 1]
steps= 4 list= [1, 3, 4, 5, 6]
list after sorting using insertion sort: [1, 3, 4, 5, 6]
>>>
Thursday 25 October 2018
Data File Handling in C++
12-D Blue-print July-2018 (24 marks 1 hour test)
* CBSE Board paper Text file 2mark problem video:
( 9 minutes) click here
* CBSE Board paper output finding in the file 1 mark:
Click Here
* CBSE Board Paper output finding file handling-2017 1 mark: click Here
* CBSE final computer science exam's Binary file based Question in c++-2016 Click Here
*GET 100% MARKS IN COMPUTER SCIENCE 12th CBSE - 06marks(FILE HANDLING)-20minutes: Click Here
Date of Test: 27-07-2018, Friday
Q2. OOPS (12 marks
Set-1
1. Direct question-2 marks
2. Constructor and Destructor-2marks
3. Class Writing Program -4marks
4. Inheritance Program Problem solving -4 marks
Q2. Data File Handling and OOPS (12 marks)
Set-2
1. Pointer Programming output probem-2 marks
2. Output problem Binary Programming-1 marks
3. Text file logic(function only) writing -2 marks
4. Binary File logic(function only) writing-3 marks
5. Class Writing Program -4 marks
5. Class Writing Program -4 marks
Friday 12 October 2018
April-18 Q.No.-1 C++ Revision Tour and11th Syllabus (12)
* Chapter 01 or Unit 01 4 years Question with Answer: Click Here 2018, 17, 16, 15)
* CLASS 12 BOARD EXAM SOLVED 2016, 2017 COMPUTER SCIENCE QUESTION PAPER C++- 36minutes: click Here
* CLASS 12-D COMMUNICATION AND * * *NETWORK CONCEPTS IN HINDI(38 MINUTES) : click here
Monday 8 October 2018
Sunday 7 October 2018
Q. No. 7 Computer Networking (10): Class 12th CS
2. NETWORKING AND COMMUNICATION || VIDEO 1 || TOPOLOGY
AND PLACEMENT OF DEVICES|| GET 100% MARKS IN CS : (7 minutes) :Click Here
CLASS 12 CS COMMUNICATION AND NETWORK CONCEPTS PART 1 IN HINDI:
Click Here
Evolution of Networking: ARPANET,
Internet, Interspace Different ways of sending data across the network with
reference to switching techniques (Circuit and Packet switching).
Data
Communication terminologies: Concept of Channel, Bandwidth (Hz, KHz, MHz)
and Data transfer rate (bps, Kbps, Mbps, Gbps, Tbps).
Transmission
media: Twisted pair cable, coaxial cable, optical fiber, infrared, radio
link, microwave link and satellite link.
Network devices: Modem, RJ45 connector, Ethernet Card, Router,
Switch, Gateway, wifi card.
Network Topologies and types: Bus,
Star, Tree, PAN, LAN, WAN, MAN.
Network
Protocol: TCP/IP, File Transfer Protocol (FTP), PPP, SMTP, POP3 Remote
Login (Talent), and Internet Wireless/Mobile Communication protocol such as
GSM, CDMA, GPRS, and WLL.
Mobile Telecommunication Technologies : 1G, 2G, 3G and 4G; Mobile
processors;
Electronic mail protocols such
as SMTP, POP3
Protocols for Chat and Video
Conferencing VOIP
Wireless technologies such as
Wi-Fi and WiMax
Network Security Concepts:
Threats
and prevention from Viruses, Worms, Trojan horse, Spams
Use of Cookies, Protection using
Firewall, https;
ndia
IT Act, Cyber Law, Cyber Crimes, IPR issues, hacking.
Introduction
To Web services: WWW, Hyper Text Markup Language (HTML), Extensible Markup
Language (XML); Hyper Text Transfer Protocol (HTTP); Domain Names; URL;
Website, Web browser, Web Servers; Web Hosting, Web Scripting – Client side (VB
Script, Java Script, PHP) and Server side (ASP, JSP, PHP), Web 2.0 (for social
networking)
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